### Question 6.17

Here's a neat trick: if I write

    	int realarray[10];
    	int *array = &realarray[-1];

I can treat `array` as if it were a 1-based array.

Although this technique is attractive (and was used in old editions of the book Numerical Recipes in C), it does not conform to the C standards. Pointer arithmetic is defined only as long as the pointer points within the same allocated block of memory, or to the imaginary ``terminating'' element one past it; otherwise, the behavior is undefined, even if the pointer is not dereferenced. The code above could fail if, while subtracting the offset, an illegal address were generated (perhaps because the address tried to ``wrap around'' past the beginning of some memory segment).

References: K&R2 Sec. 5.3 p. 100, Sec. 5.4 pp. 102-3, Sec. A7.7 pp. 205-6
ANSI Sec. 3.3.6
ISO Sec. 6.3.6
Rationale Sec. 3.2.2.3

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