### Question 6.1

I had the definition `char a[6]` in one source file, and in another I declared `extern char *a`. Why didn't it work?

The declaration `extern char *a` simply does not match the actual definition. The type pointer-to-type-T is not the same as array-of-type-T. Use `extern char a[]`.

References: ANSI Sec. 3.5.4.2
ISO Sec. 6.5.4.2
CT&P Sec. 3.3 pp. 33-4, Sec. 4.5 pp. 64-5

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